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Epimorphisms in varieties of De Morgan monoids

AMS Spring Western Virtual Sectional Meeting

T. Moraschini and J.J. Wannenburg and J.G. Raftery

  1. Department of Philosophy, University of Barcelona, Spain

  2. Institute of Computer Science, Czech Academy of Sciences, Czech Republic

  3. Department of Mathematics and Applied Mathematics, University of Pretoria, South Africa

May 2022

This work was carried out within the project Supporting the internationalization of the Institute of Computer Science of the Czech Academy of Sciences (no. CZ.02.2.69/0.0/0.0/18_053/0017594), funded by the Operational Programme Research, Development and Education of the Ministry of Education, Youth and Sports of the Czech Republic. The project is co-funded by the EU.

Epimorphisms

Let \(\mathsf{K}\) be a variety of algebras and \(\mathbf{A},\mathbf{B} \in \mathsf{K}\). A homomorphism \(f : \mathbf{A} \rightarrow \mathbf{B}\) is an epimorphism if, whenever \(\mathbf{C} \in \mathsf{K}\) and \(g,h : \mathbf{B} \rightarrow \mathbf{C}\) are homomorphisms, \[ \text{if } g \circ f = h \circ f, \text{ then } g=h. \]

All surjective homomorphisms are epimorphisms, but, the converse need not be true.



Example
The embedding of the 3-element chain into the 4-element diamond is a (non-surjective) epimorphism in the variety of distributive lattices. This reflects the fact that lattice complements are implicitly defined (i.e., unique or non-existent) for distributive lattices, even though there is no unary term that defines them explicitly.
Example
Epimorphisms are not surjective in the variety of rings, because multiplicative inverses are implicitly (but not explicitly) definable.


We say \(\mathsf{K}\) has the epimorphism surjectivity (ES) property if all its epimorphisms are surjective.

The ES property is not in general inherited by subvarieties, because a (non-surjective) homomorphism in a variety may become an epimorphism in a subvariety.

Example
The variety of all lattices has the ES property but the variety of distributive lattices does not. The embedding above is not an epimorphism in the variety of lattices, because the above diagram extends in two distinct ways to \(\mathbf{M}_3\).

Epic subalgebras

A subalgebra \(\mathbf{A} \leqslant \mathbf{B} \in \mathsf{K}\) is epic if the inclusion map \(\mathbf{A} \hookrightarrow \mathbf{B}\) is an epimorphism, i.e., homomorphisms from \(\mathbf{B}\) to members of \(\mathsf{K}\) are determined by their restrictions to \(A\).

Let \(\mathsf{K}\) be a variety of algebras. The following are equivalent:

Thm (Campercholi 2018)
Let \(\mathsf{K}\) be an arithmetical variety whose finitely subdirectly irriducible (FSI) members form a universal class. Then \(\mathsf{K}\) has the ES property iff its FSI members lack proper epic subalgebras.

Beth property

Let \(\mathsf{K}\) be a variety of algebras that algebraizes a logic \(\,\vdash\). The following are equivalent:

De Morgan monoids

A De Morgan monoid \(\mathbf{A} = \langle A; \wedge, \vee, \cdot, \neg, e \rangle\) comprises

One can define a residual \(x \to y \colon= \neg(x \cdot \neg y)\) satisfying the law of residuation \[x \cdot y \leqslant z \text{ iff } x \leqslant y \to z,\] and the constant \(f := \neg e\).

The class \(\mathsf{DMM}\) of all De Morgan monoids form a variety.

Dunn monoids are the \(\neg\)-less (\(\wedge,\vee,\cdot,\to,e\)) subreducts of De Morgan monoids.

Negative generation

An element \(a\) of a De Morgan monoid \(\mathbf{A}\) is negative if \(a \in A^{-} := \{b \in A \colon b \leqslant e\}\). And \(\mathbf{A}\) is said to be negatively generated if \(\mathbf{A} = \textup{Sg}(A^{-})\).

Depth

Let \(\mathbf{A}\) be De Morgan monoid.

If a variety of De Morgan monoids is finitely generated, then it has finite depth (but not conversely). The depth of \(\mathbf{A}\) coincides with the usual definition of the depth of \(\mathbf{A}^{-}\).

Theorem 1

Let \(\mathsf{K}\) be a variety of De Morgan monoids such that

  1. \(\mathbf{A} = \textup{Sg}(A^{-})\) for every FSI member of \(\mathsf{K}\), and
  2. \(\mathsf{K}\) has finite depth.

Then \(\mathsf{K}\) has surjective epimorphisms.

Condition (1) can’t be dropped

Urquhart (1999) showed that the crystal lattice has a proper epic subalgebra in \(\mathsf{DMM}\).

Notice that it is not negatively generated.

Reflection

Let \(\mathbf{D}\) be a Dunn monoid.

  • There is a unique way of turning the structure into a De Morgan monoid \(R(\mathbf{D}) = \langle D \cup D' \cup \{\bot,\top\}; \wedge, \vee, \cdot, \neg, e \rangle\) of which \(\mathbf{D}\) is a subreduct and where \(\neg\) extends \('\).
  • If \(\mathsf{K}\) is a class of Dunn monoids we define \(\mathbb{R}(\mathsf{K}) := \mathbb{V}(\{R(\mathbf{D}) : \mathbf{D} \in \mathsf{K}\})\).

Properties of reflections

Let \(\mathbf{D}\) be a Dunn monoid and \(\mathsf{K}\) a variety of Dunn monoids.

Condition (2) can’t be dropped

Bezhanishvili, M., and R. exhibits a Brouwerian algebra \(\mathbf{A}_1\) that generates a variety without the ES property.

\(R(\mathbf{A}_1)\) has infinite depth and has a proper \(\mathbb{R}(\mathbf{A}_1)\)-epic subalgeba.

For every \(n \in \omega\), consider the depicted Brouwerian algebra \(\mathbf{B}_n\). Let \(F := \{\mathbf{B}_n : n \in \omega \}\). Adapting Bezhanishvili\(^2\) and de Jongh (2008): for every different pair \(T,S \subseteq F\), we get \(\mathbb{V}(T) \neq \mathbb{V}(S)\).

For every \(T \subseteq F\), we show that \(\mathbb{V}(T,\mathbf{A}_1)\) is locally finite and fails to have the ES property, and the map \[\mathbb{V}(T) \mapsto \mathbb{V}(T,\mathbf{A}_1)\] is injective.

Using reflections we get:

Thm

There is \(2^{\aleph_0}\) (locally finite) varieties of De Morgan monoids (of infinite depth) that don’t have the ES property.

Semilinearity

A De Morgan monoid will be called semilinear if it is a subdirect product of totally ordered algebras. These form a variety axiomatized by \(e \leqslant (x \to y) \vee(y \to x)\).

Recall that idempotent (\(x=x \cdot x\)) De Morgan monoids are called Sugihara monoids. They are negatively generated generated and form a locally finite variety.

The variety of Sugihara monoids is generated by the algebra \(\mathbf{Z}^*\), which is the natural chain of nonzero integers (with \(-\) as \(\neg\)), \[ x \cdot y = \begin{cases} \text{whichever of }x,y\text{ has} \\ \quad\text{ a greater absolute value} \\ \text{or } x \wedge y \text{ if } \lvert x \rvert = \lvert y \rvert. \end{cases}\]

Here, \(e = 1\), so \(f = -1\).




\(\mathbf{Z}^*\) has a homomorphic image \(\mathbf{Z}\) in which just \(1\) and \(-1\) are identified.

Up to isomorphism, \(\mathbf{Z}\) could be defined like \(\mathbf{Z}^*\) on the set of all integers.

Then \(\mathbf{Z} \models f = e \,(= 0)\).

Algebras with \(f = e\) are called odd.

The variety of odd Sugihara monoids (\(\mathsf{OSM}\)) is generated by \(\mathbf{Z}\).

Let \(\mathbf{S}\) be a totally ordered odd Sugihara monoid and let \(\mathcal{X} = \{ \mathbb{X}_c : c \in S\}\) such that each \(\mathbb{X}_c\) is a chain with greatest element \(c\).

Let \(\mathbf{S} \otimes \mathcal{X}\) denote the algebra on \(\bigcup \{ X_c : c \in S \}\) with the lexicographic total order, where for \(a,b \in S\) and \(x \in X_a, y \in X_b\), \[ x \cdot y = \begin{cases} x \wedge y &\text{if } a=b \leqslant e \\ x \vee y &\text{if } e < a = b \\ x &\text{if } a \neq b \text{ and } a \cdot^{\mathbf{S}} b = a \\ y &\text{if } a \neq b \text{ and } a \cdot^{\mathbf{S}} b = b \end{cases} \] \[ x \to y = \begin{cases} (a \to e) \vee y &\text{if } x \leqslant y \\ (a \to e) \wedge y &\text{if } y < x \end{cases} . \]

Thm (Gil-Férez, Jipsen and Metcalfe, 2020)
\(\mathbf{S}\oplus \mathcal{X}\) is a totally ordered idempotent Dunn monoid. Moreover, every totally ordered idempotent Dunn monoid has this form.

Generalized Sugihara monoids are negatively generated semilinear idempotent Dunn monoid, and they form a locally finite variety \(\mathsf{GSM}\) (Raftery, 2007).

The totally ordered members are \(\mathbf{S}\oplus \mathcal{X}\) as above, but \(X_c = \{c\}\) for every \(e \leqslant c \in S\).

Thm
If a totally ordered Dunn monoid is generated by idempotent elements, then it is idempotent.

Therefore, every variety of negatively generated semilinear Dunn monoids is a subvariety of \(\mathsf{GSM}\).

Thm (M., R. and W., 2019)

A totally ordered De Morgan monoid \(\mathbf{A}\) is negatively generated iff

  1. \(\mathbf{A}\) is a Sugihara monoid, or
  2. \(A = (\bot] \cup R(\mathbf{D}) \cup [\top)\) where \((\bot]\) and \([\top)\) are chains of idempotents, and \(\mathbf{D}\) is a totally ordered member of \(\mathsf{GSM}\).

This can be used to show that the class of negatively generated semilinear De Morgan monoids is a locally finite variety.

Theorem 2

Every variety of negatively generated semilinear De Morgan monoids has surjective epimorphisms.

The same is true for generalized Sugihara monoids.

This result therefore generalizes the following results, see (Bezhanishvili, M. and R., 2017):

Negative generation can’t be dropped

Thm

\(\text{Sg}^{\mathbf{A}_2}(4) = \{0,1,4,8\}\) is a proper epic subalgebra of \(\mathbf{A}_2\) in the variety of semilinear Dunn/De Morgan monoids.

Proof

Let \(\mathbf{C}\) be a totally ordered De Morgan monoid and \(g,h : \mathbf{A}_2 \rightarrow \mathbf{C}\) such that \(g(4) = h(4)\).

Suppose w.l.o.g. \(g(2) \leqslant h(2)\). \[g(2) \cdot h(2) \leqslant h(2) \cdot h(2) = h(4) = g(4)\] \[h(2) \leqslant g(2) \to g(4) = g(2)\] So, \(g(2) = h(2)\), but then \(g = h\).

\(\cdot\) is integer multiplication truncated at \(8\). Note that \(2 = 2 \to 4\).

Thm

  • Epimorphisms are surjective in the variety of semilinear idempotent Dunn monoids.
  • The variety generated by all simple semilinear idempotent Dunn monoids has surjective epimorphisms.

Thm

The variety generated by the Dunn monoid \(\mathbf{A} = \mathbf{S}_3 \otimes \{\{-1\},\{0\},\{c>1\}\}\) does not have the ES property.

Proof

We show that the integer subalgebra of \(\mathbf{A}\) is epic. Let \(\mathbf{C}\) be a subdirectly irreducible member of \(\mathbb{V}(\mathbf{A})\), and \(g,h : \mathbf{A} \rightarrow \mathbf{C}\) agree on the integers. W.l.o.g. \(g\) and \(h\) is non-trivial. Since \(\mathbf{A}\) is simple, \(g,h\) are embeddings. So, by Jonsson’s theorem, \(\mathbf{C} = \mathbf{A}\). But then \(g=h\).





thank you